Question - 2.2 - Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.
Given, % of benzene by mass = 30%
Thus, % of solvent (carbon tetrachloride) = 70%
Mole fraction of benzene in the given solution = ?
This means, 30g of benzene (C6 H 6) is dissolved in 70 g of CCl 4
Now, Molecular mass of benzene (C6 H6 ) = (12 x 6) + (1 x 6) = 78 g mol – 1
Molecular mass of carbon tetrachloride (CCl4 ) = 12 + (35.5 x 4 ) = 154 g mol – 1
Therefore, Number of moles of C 6H 6
And, number of moles of CCl4
Thus, mole fraction of benzene in the given solution
Thus, mole fraction of benzene in the given solution = 0.457