Chemistry - Class Twelve

Solutions

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Solution of NCERT In Text Questions 2.2

Question - 2.2 - Calculate the mole fraction of benzene in solution containing 30% by mass in carbon tetrachloride.

Solution:

Given, % of benzene by mass = 30%

Thus, % of solvent (carbon tetrachloride) = 70%

Mole fraction of benzene in the given solution = ?

This means, 30g of benzene (C6 H 6) is dissolved in 70 g of CCl 4

Now, Molecular mass of benzene (C6 H6 ) = (12 x 6) + (1 x 6) = 78 g mol – 1

Molecular mass of carbon tetrachloride (CCl4 ) = 12 + (35.5 x 4 ) = 154 g mol – 1

Therefore, Number of moles of C 6H 6 Solutions class 12 chemistry - NCERT In Text Solution5

Solutions class 12 chemistry - NCERT In Text Solution6

And, number of moles of CCl4 Solutions class 12 chemistry - NCERT In Text Solution7

Solutions class 12 chemistry - NCERT In Text Solution8

Thus, mole fraction of benzene in the given solution

Solutions class 12 chemistry - NCERT In Text Solution9
Solutions class 12 chemistry - NCERT In Text Solution10

Thus, mole fraction of benzene in the given solution = 0.457

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Topics covered in this chapter of Solutions

1. Solutions

2. Types of Solutions

3. Solutions - Concentration

4. Solution of NCERT In Text Questions

Class 12 Biology

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