NCERT Exercise 2.3 Solution

Fractions and Decimals 7th Math

NCERT Exercise 2.3 Solution

Question (1) Find:

(i) `1/4` of (a) `1/4`

Solution :

Given, to find `1/4` of `1/4`

We know that, the word "of" stands for multiplication in mathematics, thus after replacing "of" with sign of multiplication (×), we get

`1/4xx1/4`

Now, to multiply two or more fractions numerator is multiplied with numerator and denominator is multiplied with denominator.

`=(1xx1)/(4xx4)`

`=1/16` Answer

(i) `1/4` of (b) `3/5`

Solution :

Given, to find `1/4` of `3/5`

We know that, the word "of" stands for multiplication in mathematics, thus after replacing "of" with sign of multiplication (×), we get

`=1/4xx3/5`

Now, to multiply two or more fractions numerator is multiplied with numerator and denominator is multiplied with denominator.

`=(1xx3)/(4xx5)`

`=3/20` Answer

(i) `1/4` of (c) `4/3`

Solution :

Given, to find `1/4` of `4/3`

We know that, the word "of" stands for multiplication in mathematics, thus after replacing "of" with sign of multiplication (×), we get

`=1/4xx4/3`

Now, to multiply two or more fractions numerator is multiplied with numerator and denominator is multiplied with denominator.

`=(1xxcancel4)/(cancel4xx3)`

`=1/3` Answer

(ii) `1/7` of (a) `2/9`

Solution :

Given, to find `1/7` of `2/9`

We know that, the word "of" stands for multiplication in mathematics, thus after replacing "of" with sign of multiplication (×), we get

`=1/7xx2/9`

Now, to multiply two or more fractions numerator is multiplied with numerator and denominator is multiplied with denominator.

`=(1xx2)/(7xx9)`

`=2/63` Answer

(ii) `1/7` of (b) `6/5`

Solution :

Given, to find `1/7` of `6/5`

We know that, the word "of" stands for multiplication in mathematics, thus after replacing "of" with sign of multiplication (×), we get

`=1/7xx6/5`

Now, to multiply two or more fractions numerator is multiplied with numerator and denominator is multiplied with denominator.

`=(1xx6)/(7xx5)`

`=6/35` Answer

(ii) `1/7` of (c) `3/10`

Solution :

Given, to find `1/7` of `3/10`

We know that, the word "of" stands for multiplication in mathematics, thus after replacing "of" with sign of multiplication (×), we get

`=1/7xx3/10`

Now, to multiply two or more fractions numerator is multiplied with numerator and denominator is multiplied with denominator.

`=(1xx3)/(7xx10)`

`=3/70` Answer

Question (2) Multiply and reduce to lowest form (if possible):

(i) `2/3xx2 2/3`

Solution :

Given, `2/3xx2 2/3`

`= 2/3 xx 8/3`

Now, to multiply two or more fractions numerator is multiplied with numerator and denominator is multiplied with denominator.

`=(2xx8)/(3xx3)`

`= 16/9`

`=1 7/9` Answer

(ii) `2/7xx7/9`

Solution :

Given, `2/7xx7/9`

Now, to multiply two or more fractions numerator is multiplied with numerator and denominator is multiplied with denominator.

`=(2xxcancel7)/(cancel7xx9)`

`=2/9` Answer

(iii) `3/8xx6/4`

Solution :

Given, `3/8xx6/4`

Now, to multiply two or more fractions numerator is multiplied with numerator and denominator is multiplied with denominator.

`=(3xx6)/(8xx4)`

`=(3xx3xxcancel2)/(8xx2xxcancel2)`

`= 9/16` Answer

(iv) `9/5xx3/5`

Solution :

Given, `9/5xx3/5`

Now, to multiply two or more fractions numerator is multiplied with numerator and denominator is multiplied with denominator.

`=(9xx3)/(5xx5)`

`=27/25`

`=1 2/25` Answer

(v) `1/3xx15/8`

Solution :

Given,` 1/3xx15/8`

Now, to multiply two or more fractions numerator is multiplied with numerator and denominator is multiplied with denominator.

`=(1xx15)/(3xx8)`

`=(1xx5xxcancel3)/(cancel3xx8)`

`=5/8` Answer

(vi) `11/2xx3/10`

Solution :

Given, `11/2xx3/10`

Now, to multiply two or more fractions numerator is multiplied with numerator and denominator is multiplied with denominator.

`=(11xx3)/(2xx10)`

`=33/20`

`=1 13/20` Answer

(vii) `4/5xx12/7`

Solution :

Given, `4/5xx12/7`

Now, to multiply two or more fractions numerator is multiplied with numerator and denominator is multiplied with denominator.

`=(4xx12)/(5xx7)`

`=48/35`

`=1 13/35` Answer

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