NCERT Exercise 9.2 Question 3
Rational Numbers 7th Math
NCERT Exercise 9.2 Question 3
In this chapter, we are learning mathematical operations on rational numbers. In Question Number 2 of the chapter of NCERT Exercise 9.2, math, class seven, five questions based on the multiplication of rational numbers have been given. In these questions, one rational number is to be multiplied by another given one. This means we have to find the product of the given rational numbers.
NCERT Exercise 9.2 Question Number 3
Question(3) Find the product
(i) 9/2 × (– 7/4)
Solution :
Given, 9/2 × (– 7/4)
To find the product of two rational numbers the numerator is multiplied by the numerator of the given rational numbers and the denominator is multiplied by the denominator.
= 9 × (– 7)/2 × 4
= – 63/8
Since there is no common factor other than 1 in the numerator and denominator, thus the obtained rational number is in its simplest form.
Thus, – 63/8 Answer
Question (3) (ii) 3/10 × (– 9)
Solution :
Given, 3/10 × (– 9)
= 3/10 × (– 9)/1
To find the product of two rational numbers the numerator is multiplied by the numerator of the given rational numbers and the denominator is multiplied by the denominator.
= 3 × (– 9)/10 × 1
= – 27/10
Since there is no common factor other than 1 in the numerator and denominator, thus the obtained rational number is in its simplest form.
Thus, – 27/10 Answer
Question (3) (iii) – 6/5 × 9/11
Solution :
Given, – 6/5 × 9/11
To find the product of two rational numbers the numerator is multiplied by the numerator of the given rational numbers and the denominator is multiplied by the denominator.
= – 6 × 9/5 × 11
= – 54/55
Since there is no common factor other than 1 in the numerator and denominator, thus the obtained rational number is in its simplest form.
Thus, – 54/55 Answer
Question (3) (iv) 3/7 × (– 2/5)
Solution :
Given, 3/7 × (– 2/5)
To find the product of two rational numbers the numerator is multiplied by the numerator of the given rational numbers and the denominator is multiplied by the denominator.
= 3 × (– 2)/7 × 5
= – 6/35
Since there is no common factor other than 1 in the numerator and denominator, thus the obtained rational number is in its simplest form.
Thus, – 6/35 Answer
Question (3) (v) 3/11 × 2/5
Solution :
Given, 3/11 × 2/5
To find the product of two rational numbers the numerator is multiplied by the numerator of the given rational numbers and the denominator is multiplied by the denominator.
= 3 × 2/11 × 5
= 6/55
Since there is no common factor other than 1 in the numerator and denominator, thus the obtained rational number is in its simplest form.
Thus, 6/55 Answer
Question (3) (vi) 3/ – 5 × – 5/3
Solution :
Given, 3/ – 5 × – 5/3
= 3/– 5 × – 5/3
= 1 Answer
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