Practical Geometry - 8th math

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NCERT Exercise 4.3


Construction of quadrilateral when two adjacent sides and three angles are known

Class 8 math Practical Geometry Construction of quadrilateral when two adjacent sides and three angles are knownSolution of NCERT Exercise 4.3 Question (1) Construct the following quadrilaterals

(i) Quadrilateral MORE

MO = 6 cm

OR = 4.5 cm

∠M = 600

∠O = 1050

∠R = 1050

Solution

First of all construct a rough sketch of the given quadrilateral.

 practical geometry ncert exercise 4.3 construction of quadrilateral-1

Step (i) First of all to draw the side MO = 6 cm. Draw a horizontal line and cut 6 cm from it using a compass and a measuring scale.

 practical geometry ncert exercise 4.3 construction of quadrilateral-2

Step (ii) On the point O an angle of 105o is made.

 practical geometry ncert exercise 4.3 construction of quadrilateral-3

Step (iii) On the side OR an arc of radius 4.5 cm is drawn. This the side OR = 4.5cm

 practical geometry ncert exercise 4.3 construction of quadrilateral-4

Step (iv) On point R on the side OR the given angle 105o is made.

 practical geometry ncert exercise 4.3 construction of quadrilateral-5

Step (v) Now, draw an angle equal to 60o on point M and stretch the line upto ray of angle made on point R to complete the given quadrilateral.

 practical geometry ncert exercise 4.3 construction of quadrilateral-6

This is the construction of given quadrilateral.

Class 8 math Practical Geometry Construction of quadrilateral Solution of NCERT Exercise 4.3 Question (1) (ii) Quadrilateral PLAN

PL = 4 cm

LA 6.5 cm

∠P = 90o

∠A = 10o

∠N = 85o

Solution

First of all a rough sketch of the given quadrilateral is drawn to estimate the construction.

 practical geometry ncert exercise 4.3 construction of quadrilateral-7

Here, since angle L is not given thus, without knowing the angle L it is not possible to draw the given quadrilateral because ∠L is the angle made between given adjacent sides.

Now, we know that, sum of measure of angles of a quadrilateral = 3600

Thus, 85o + 90o + ∠L + 110o = 360o

⇒ 285o + ∠L = 360o

⇒ ∠L = 360o – 285o

`=>/_L=75^o`

Step (i) Draw a horizontal line and cut it equal to 4 cm using a compass and a measuring scale.

 practical geometry ncert exercise 4.3 construction of quadrilateral-8

Step(ii) Make an angle equal to `75^o` on point L and draw a line for this angle.

 practical geometry ncert exercise 4.3 construction of quadrilateral-9

Step (iii) Measure a length of `6.5` cm using a compass and scale and make an arc of this radius 6.5 cm on side LA.

 practical geometry ncert exercise 4.3 construction of quadrilateral-10

Step (iv) Draw and angle equal to 110o on point A and draw a line for this angle.

 practical geometry ncert exercise 4.3 construction of quadrilateral-11

Step (v) Draw an angle equal to 90o on point P. And draw a line which meets on point N, i.e. AN to complete the given quadrilateral.

 practical geometry ncert exercise 4.3 construction of quadrilateral-12

This is the construction of given quadrilateral.

Class 8 math Practical Geometry Construction of quadrilateral Solution of NCERT Exercise 4.3 Question (1) (iii) Parallelogram HEAR

HE = 5 cm

EA = 6 cm

∠R = 850

Solution

First of all a rough sketch of the given parallelogram is drawn to estimate the construction of given parallelogram.

 practical geometry ncert exercise 4.3 construction of quadrilateral-13

Here, as given ∠R = 85o

And we know that, opposite angles of a parallelogram are equal in measurement.

Here, since ∠E is the opposite angle of ∠R

Thus, ∠E = ∠R

Thus, ∠E = 85o

Now, we know that, the sum of adjacent angles of a parallelogram is equal = 180o

Thus, ∠R + ∠H = 180o

⇒ 85o + ∠H = 180o

⇒ ∠H = 180o – 85o

⇒ ∠H = 95o

Step (i) To draw the side HE = 5 cm of the given parallelogram, a horizontal line is drawn and cut it using a compass and measuring scale equal to 5 cm.

 practical geometry ncert exercise 4.3 construction of quadrilateral-14

Step (ii) Angle E = 85o is drawn on point E using a protector.

Step (ii) And using a compass an arc of radius 6 cm is made on the ray of angle made on point E

 practical geometry ncert exercise 4.3 construction of quadrilateral-15

Step (iii) Mark an arc of radius 6 cm on the ray coming out from the point E at an angle of 85o. And name this point as A.

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Step (iv) Draw and angle equal to 95o on point H and draw a line for this angle.

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Since AE||HR

And, we know that the opposite sides of a parallelogram are equal in measure.

Thus, HR = EA = 6 cm

Step (v) Mark an arc of radius 6cm on line coming out from the point H. Name this point as R.

 practical geometry ncert exercise 4.3 construction of quadrilateral-18

Step (vi) Now draw a line to connect point R and A to complete the given quadrilateral.

 practical geometry ncert exercise 4.3 construction of quadrilateral-19

This is the construction of given quadrilateral.

Class 8 math Practical Geometry Construction of quadrilateral Solution of NCERT Exercise 4.3 Question (1) (iv) Rectangle OKAY

OK = 7 cm

KA = 5 cm

Solution

First of all a rough sketch of the given rectangle is made to estimate the construction.

 practical geometry ncert exercise 4.3 construction of quadrilateral-20

We know that, a rectangle has all angles equal to 90o. And opposite sides are equal.

Step (i) Draw a horizontal line and cut it equal to 7 cm using a compass and a measuring scale.

 practical geometry ncert exercise 4.3 construction of quadrilateral-20

Step (ii) Draw an angle equal to 90o at point K and draw a line for this angle.

Step (iii) Draw and arc of radius 5 cm on the line of the angle of 90o made on point K. And mark the point of arc meeting at line as A. This is side KA = 5cm.

 practical geometry ncert exercise 4.3 construction of quadrilateral-21

Step (iv) Draw an angle equal to 90o at point P and draw a line for this angle. Because in a rectangle opposite sides are parallel and angle made by the side of rectangle is equal to 90o.

Step (v) Draw and arc of radius 5 cm on the line of the angle of 90o made on point O. And mark the point of arc meeting at line as Y. This is side OY = 5cm. Because opposite side of a rectangle are equal.

 practical geometry ncert exercise 4.3 construction of quadrilateral-22

Step (vi) Join the point Y and A and complete the rectangle. This is side YA = 7cm

 practical geometry ncert exercise 4.3 construction of quadrilateral-23

This is the construction of given rectangle.

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